Python 嵌套的字典(dict)转成object对象的方法

1、使用自定义class

class obj(object):
    def __init__(self, d):
        for a, b in d.items():
            if isinstance(b, (list, tuple)):
               setattr(self, a, [obj(x) if isinstance(x, dict) else x for x in b])
            else:
               setattr(self, a, obj(b) if isinstance(b, dict) else b)
d = {'a': 1, 'b': {'c': 2}, 'd': ["hi", {'foo': "cjavapy"}]}
o = obj(d)
print(o)
print(o.a)
print(o.b)
print(o.d)
print(o.d[1].foo)

2、使用json

import json
class obj(object):
    def __init__(self, dict_):
        self.__dict__.update(dict_)
def dict2obj(d):
    return json.loads(json.dumps(d), object_hook=obj)
d = {'a': 1, 'b': {'c': 2}, 'd': ['hi', {'foo': 'cjavapy'}]}
o = dict2obj(d)
print(o)
print(o.a)
print(o.b)
print(o.d)
print(o.d[1].foo)

3、使用namedtuple

参考文档：http://docs.python.org/library/collections.html?highlight=collections#namedtuple-factory-function-for-tuples-with-named-fields

from collections import namedtuple
class struct(object):
    def __new__(cls, data):
        if isinstance(data, dict):
            return namedtuple(
                'struct', data.keys()
            )(
                *(struct(val) for val in data.values())
            )
        elif isinstance(data, (tuple, list, set, frozenset)):
            return type(data)(struct(_) for _ in data)
        else:
            return data
d = {'a': 1, 'b': {'c': 2}, 'd': ['hi', {'foo': 'cjavapy'}]}
o = struct(d)
print(o)
print(o.a)
print(o.b)
print(o.d)
print(o.d[1].foo)