Python 获取两个list列表中元素平均值的方法及示例代码

mylist1 = [["lemon", 0.1], ["egg", 0.1], ["muffin", 0.3], ["chocolate", 0.5]]
mylist2 = [["chocolate", 0.5], ["milk", 0.2], ["carrot", 0.8], ["egg", 0.8]]

结果均值列表：

myoutput = [["chocolate", 0.5], ["egg", 0.45]]

1､使用字典(dict)和for循环实现

mylist1 = [["lemon", 0.1], ["egg", 0.1], ["muffin", 0.3], ["chocolate", 0.5]]
mylist2 = [["chocolate", 0.5], ["milk", 0.2], ["carrot", 0.8], ["egg", 0.8]]
l1_as_dict = dict(mylist1)
myoutput = []
for item,price2 in mylist2:
    if item in l1_as_dict:
        price1 = l1_as_dict[item]
        myoutput.append([item, (price1+price2)/2])
print(myoutput)

或者

d = {}
for lst in (mylist1, mylist2):
    for i, v in lst:
        d.setdefault(i, []).append(v)   # 也可以使用 collections.defaultdict
[[k, sum(v)/len(v)] for k, v in d.items() if len(v) > 1]

或者

d_list1 = dict(mylist1)
d_list2 = dict(mylist2)
[[k, (v+d_list2[k])/2] for k, v in d_list1.items() if k in d_list2]
#[['egg', 0.45], ['chocolate', 0.5]]

2､使用pandas实现

安装pandas:

pip install pandas

实现代码：

import pandas as pd
df1 = pd.DataFrame(mylist1)
df2 = pd.DataFrame(mylist2)
res = pd.merge(df1, df2, on=0)
res['mean'] = res.mean(axis=1)
res.drop(['1_x', '1_y'], 1, inplace=True)
res.values.tolist()
[['egg', 0.45], ['chocolate', 0.5]]